Pages

Monday 29 April 2013

Alkyl Halides

Imagine that a pair of crystallizing dishes are placed on an overhead projector as shown in the figure below. An alkene is added to the dish in the upper-left corner of the projector and an alkane is added to the dish in the upper-right corner. A few drops of bromine dissolved in chloroform (CHCl3) are then added to each of the crystallizing dishes.
The characteristic red-orange color of bromine disappears the instant this reagent is added to the alkene in the upper-left corner as the Br2 molecules add across the C=C double bond in the alkene.
The other crystallizing dish picks up the characteristic color of a dilute solution of bromine because this reagent doesn't react with alkanes under normal conditions.
If the crystallizing dish in the upper-right corner is moved into the center of the projector, however, the color of the bromine slowly disappears. This can be explained by noting that alkanes react with halogens at high temperatures or in the presence of light to form alkyl halides.
The light source in an overhead projector is intense enough to initiate this reaction, although the reaction is still significantly slower than the addition of Br2 to an alkene.
The reaction between an alkane and one of the halogens (F2, Cl2, Br2, or I2) can be understood by turning to a simpler example.
CH4(g) + Cl2(g) CH3Cl(g) + HCl(g)
This reaction has the following characteristic properties.
  • It doesn't take place in the dark or at low temperatures.
  • It occurs in the presence of ultraviolet light or at temperatures above 250ºC.
  • Once the reaction gets started, it continues after the light is turned off.
  • The products of the reaction include CH2Cl2 (dichloromethane), CHCl3 (chloroform), and CCl4 (carbon tetrachloride), as well as CH3Cl (chloromethane).
  • The reaction also produces some C2H6.
These facts are consistent with a chain-reaction mechanism that involves three processes: chain initiation, chain propagation, and chain termination.
return to top

Chain Initiation
A Cl2 molecule can dissociate into a pair of chlorine atoms by absorbing energy in the form of either ultraviolet light or heat.
Cl2 2 Cl ·

Ho = 243.4 kJ/molrxn
The chlorine atom produced in this reaction is an example of a free radical -- an atom or molecule that contains one or more unpaired electrons.
Chain Propagation
Free radicals, such as the Cl· atom, are extremely reactive. When a chlorine atom collides with a methane molecule, it can abstract a hydrogen atom to form HCl and a CH3· radical.
CH4 + Cl· CH3· + HCl

Ho = -16 kJ/molrxn
If the CH3· radical then collides with a Cl2 molecule, it can remove a chlorine atom to form CH3Cl and a new Cl· radical.
CH3· + Cl2 CH3Cl + Cl·

Ho = -87 kJ/molrxn
Because a Cl· atom is generated in the second reaction for every Cl· atom consumed in the first, this reaction continues in a chain-like fashion until the radicals involved in these chain-propagation steps are destroyed.
Chain Termination
If a pair of the radicals that keep the chain reaction going collide, they combine in a chain-terminating step. Chain termination can occur in three ways.
2 Cl · Cl2

Ho = -243.4 kJ/molrxn
CH3· + Cl · CH3Cl

Ho = -330 kJ/molrxn
2 CH3· CH3CH3

Ho = -350 kJ/molrxn
Because the concentration of the radicals is relatively small, these chain-termination reactions are relatively infrequent.
This chain-reaction mechanism for free-radical reactions explains the observations listed for the reaction between CH4 and Cl2.
  • The reaction doesn't occur in the dark or at low temperatures because energy must be absorbed to generate the free radicals that carry the reaction.
Cl2 2 Cl·

Ho = 243.4 kJ/molrxn
  • The reaction occurs in the presence of ultraviolet light because a UV photon has enough energy to dissociate a Cl2 molecule to a pair of Cl· atoms. The reaction occurs at high temperatures because Cl2 molecules can dissociate to form Cl· atoms by absorbing thermal energy.
  • The reaction continues after the light has been turned off because light is only needed to generate the Cl· atoms that start the reaction. The chain reaction then converts CH4 into CH3Cl without consuming these Cl· atoms.
CH4 + Cl· CH3· + HCl
CH3· + Cl2 CH3Cl + Cl·
  • The reaction doesn't stop at CH3Cl because the Cl· atoms can abstract additional hydrogen atoms to form CH2Cl2, CHCl3, and eventually CCl4.
CH3Cl + Cl· CH2Cl· + HCl
CH2Cl· + Cl2 CH2Cl2 + Cl·, and so on
  • The formation of C2H6 is a clear indication that the reaction proceeds through a free-radical mechanism. When two CH3· radicals collide, they combine to form a ethane molecule.
2 CH3· CH3CH3
Free-radical halogenation of alkanes provides us with another example of the role of atom-transfer reactions in organic chemistry. The net effect of this reaction is to oxidize a carbon atom by removing a hydrogen from this atom.
CH4 + Cl2 CH3Cl + HCl
-4


-2

The reaction, however, doesn't involve the gain or loss of electrons. It occurs by the transfer of a hydrogen atom in one direction and a chlorine atom in the other

No comments:

Post a Comment

 

Sample text

Sample Text