ATOMIC AND PHYSICAL PROPERTIES OF THE GROUP 1 ELEMENTS
This page explores the trends in some atomic and physical properties
of the Group 1 elements - lithium, sodium, potassium, rubidium and
caesium. You will find separate sections below covering the trends in
atomic radius, first ionisation energy, electronegativity, melting and
boiling points, and density. Even if you aren't currently interested in all these things, it would probably pay you to read the whole page. The same ideas tend to recur throughout the atomic properties, and you may find that earlier explanations help to you understand later ones. Trends in Atomic Radius | |||||||
Note: You will find atomic radius covered in detail in another part of this site. If you choose to follow this link, use the BACK button on your browser to return quickly to this page. | |||||||
Explaining the increase in atomic radius The radius of an atom is governed by
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Note: If you aren't sure about writing electronic structures using s and p notation it might be a good idea to follow this link before you go on. Use the BACK button on your browser to return quickly to this page. | |||||||
In each case, the outer electron feels a net pull of 1+ from the
nucleus. The positive charge on the nucleus is cut down by the
negativeness of the inner electrons. The only factor which is going to affect the size of the atom is therefore the number of layers of inner electrons which have to be fitted in around the atom. Obviously, the more layers of electrons you have, the more space they will take up - electrons repel each other. That means that the atoms are bound to get bigger as you go down the Group. | |||||||
Note: You may think that this is all a bit long-winded! It is, after all, fairly obvious that atoms will get bigger if you add more layers of electrons. Why, then, bother about exploring the net pull on the electrons from the centre of the atom? It is a matter of setting up good habits. If you are talking about atoms in the same Group, the net pull from the centre will always be the same - and you could ignore it without creating problems. That isn't true if you try to compare atoms from different parts of the Periodic Table. If you don't get into the habit of thinking about all the possible factors, you are going to make mistakes. | |||||||
Trends in First Ionisation Energy
First ionisation energy is the energy needed to remove the most
loosely held electron from each of one mole of gaseous atoms to make one
mole of singly charged gaseous ions - in other words, for 1 mole of
this process: | |||||||
Note: You will find ionisation energy covered in detail in another part of this site. If you choose to follow this link, use the BACK button on your browser to return quickly to this page. | |||||||
Explaining the decrease in first ionisation energy Ionisation energy is governed by
However, as you go down the Group, the distance between the nucleus and the outer electrons increases and so they become easier to remove - the ionisation energy falls. Trends in Electronegativity Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. It is usually measured on the Pauling scale, on which the most electronegative element (fluorine) is given an electronegativity of 4.0. | |||||||
Note: You will find electronegativity covered in detail in another part of this site. If you choose to follow this link, use the BACK button on your browser to return quickly to this page. | |||||||
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Note: You might argue that the fall doesn't apply throughout the Group because both potassium and rubidium have an electronegativity of 0.8. This can't be explained just as a rounding error (as I have done elsewhere on the site in the corresponding Group 2 case), because both elements have the same electronegativity to 2 decimal places as well. Both are 0.82. I'm not clear what the reason for this is! There are various other measures of electronegativity apart from the Pauling one, and on each of these the rubidium value is indeed smaller than the potassium one. | |||||||
Explaining the decrease in electronegativity Imagine a bond between a sodium atom and a chlorine atom. Think of it to start with as a covalent bond - a pair of shared electrons. The electron pair will be dragged towards the chlorine because there is a much greater net pull from the chlorine nucleus than from the sodium one. The large pull from the chlorine nucleus is why chlorine is much more electronegative than sodium is. Now compare this with the lithium-chlorine bond. The net pull from each end of the bond is the same as before, but you have to remember that the lithium atom is smaller than a sodium atom. That means that the electron pair is going to be closer to the net 1+ charge from the lithium end, and so more strongly attracted to it. Summarising the trend down the Group As the metal atoms get bigger, any bonding pair gets further and further away from the metal nucleus, and so is less strongly attracted towards it. In other words, as you go down the Group, the elements become less electronegative. With the exception of some lithium compounds, these elements all form compounds which we consider as being fully ionic. They are so weakly electronegative that we assume that the electron pair is pulled so far away towards the chlorine (or whatever) that ions are formed. Trends in Melting and Boiling Points Explaining the trends in melting and boiling points When you melt any of these metals, the metallic bond is weakened enough for the atoms to move around, and is then broken completely when you boil the metal. The fall in melting and boiling points reflects the fall in the strength of the metallic bond. | |||||||
Note: If you aren't confident about metallic bonding you should follow this link before you go on. Use the BACK button on your browser to return quickly to this page. | |||||||
The atoms in a metal are held together by the attraction of the
nuclei to the delocalised electrons. As the atoms get bigger, the
nuclei get further away from these delocalised electrons, and so the
attractions fall. That means that the atoms are more easily pulled
apart to make a liquid and finally a gas. In the same way that we have already discussed, each of these atoms has a net pull from the nuclei of 1+. The increased charge on the nucleus as you go down the Group is offset by additional levels of screening electrons. All that matters is the distance between the nucleus and the bonding electrons. | |||||||
Note: This explanation seems fairly obvious, and works well for the Group 1 metals. However, if you have read about the corresponding Group 2 case, you will know that life isn't always so simple! | |||||||
Trends in Density
The density tends to increase as you go down the Group (apart from the fluctuation at potassium). Explaining the trend in density It is quite difficult to come up with a simple explanation for this, because the density depends on two factors, both of which are changing as you go down the Group. All of these metals have their atoms packed in the same way, so all you have to consider is how many atoms you can pack in a given volume, and what the mass of the individual atoms is. How many you can pack depends, of course, on their volume - and their volume, in turn, depends on their atomic radius. As you go down the Group, the atomic radius increases, and so the volume of the atoms increases as well. That means that you can't pack as many sodium atoms into a given volume as you can lithium atoms. However, as you go down the Group, the mass of the atoms increases. That means that a particular number of sodium atoms will weigh more than the same number of lithium atoms. So 1 cm3 of sodium will contain fewer atoms than the same volume of lithium, but each atom will weigh more. What affect will that have on the density? It is completely impossible to say unless you do some sums! | |||||||
Note: If your maths is reasonable, it isn't too difficult to work out what the density of sodium should be if you know lithium's density and have figures for relative atomic mass and atomic radius - and similarly all the rest of the way down the Group. I'm not going to waste time and space doing it, because I can't conceive of any situation when you would ever be asked to do it! If you want to try it, you will find that the density is inversely proportional to the volumes of the atoms and directly proportional to their masses. | |||||||
Saturday, 29 June 2013
ATOMIC AND PHYSICAL PROPERTIES OF THE GROUP 1 ELEMENTS
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Inorganic Chemistry
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Thankyou Pijat Panggilan Bali
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